PHP: how to create an array with one _GET value and another one that is set

Question

I am working on a call to the Youtube API. In this code the number of listings to return (maxResults) is set by the user through a form along with the search query. I want to set the maxResults myself and take away that choice from the user. In this piece of code, how can I set the maxResults to "30" instead of the $_GET['maxResults']?

 $searchResponse = $youtube->search->listSearch('id,snippet', array(
'q' => $_GET['q'],
'maxResults' => $_GET['maxResults'],
));

Thanks!

how about replacing $_GET['maxResults'] with 30..?

Sharlike
– Sharlike

2014-08-26 17:11:35 +00:00
Commented Aug 26, 2014 at 17:11 — Sharlike
– Sharlike, Commented Aug 26, 2014 at 17:11

lin · Accepted Answer · 2014-08-26 17:58:52Z

1

Cheers, try this codes my friend. And remember, always use "isset()" validation on super globals.

 $searchResponse = $youtube->search->listSearch('id, snippet', array(
     'q' => isset($_GET['q']) ? $_GET['q'] : null,
     'maxResults' => 30, //insert maxResult count here
));

edited Aug 26, 2014 at 17:58

answered Aug 26, 2014 at 17:11

lin

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3 Comments

Charlotte Dunois Over a year ago

Set doesn't mean not empty.

Barmar Over a year ago

He said he wants to NOT use the parameter from the user. This code just adds a default value.

user2382580 Over a year ago

Thanks lin - 'maxResults' => 30 works. I had an IF statement further up that checked if the parameter was set from user, preventing the this bit from executing in the first place - duh. Your isset comment helped me realize this. Cheers.

J. A. Streich · Accepted Answer · 2014-08-26 17:11:32Z

1

 $searchResponse = $youtube->search->listSearch('id,snippet', array(
 'q' => $_GET['q'],
 'maxResults' => 30,
 ));

answered Aug 26, 2014 at 17:11

J. A. Streich

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