Call a jquery function from a jquery function

Question

How can i call a jQuery function from a jQuery function, Both the function are event handler.

My function-

$("#myFunction").live("change", function(){
//I want to call my calling function here
});

My Calling Function-

$("#callingFunction").live("change", function(){

});

How can i do this? Need help!

It's really weird you name DOM elements "myFunction" and "callingFunction". They are not functions, they are DOM elements. You should give them id="element1", not id="myFunction". — Jeremy Thille
– Jeremy Thille, Commented Mar 3, 2015 at 11:56

Pranay Rana · Accepted Answer · 2015-03-03 11:51:02Z

2

you can make use of .trigger() function available in jquery library to do that.

Example

$( "#foo" ).on( "click", function() {
alert( $( this ).text() );
});
$( "#foo" ).trigger( "click" );

you can also make use of change function like as below

$( ".target" ).change(function() {
alert( "Handler for .change() called." );
});

$( "#other" ).click(function() {
$( ".target" ).change();
});

answered Mar 3, 2015 at 11:51

Pranay Rana

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Jeremy Thille · Accepted Answer · 2015-03-03 11:59:55Z

1

function doSomething(){
 /* stuff stuff stuff */
}

$("#element1").on("change", doSomething);
$("#element2").on("change", doSomething);

or

$("#element1").change(doSomething);
$("#element2").change(doSomething);

or even better, as Satpal suggested :

$("#element1, #element2").change(doSomething);

As of jQuery 1.7, live() is deprecated.

And I didn't name my elements "myFunction" and "callingFunction" as they are not functions but DOM elements.

edited Mar 3, 2015 at 11:59

answered Mar 3, 2015 at 11:51

Jeremy Thille

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1 Comment

Satpal Over a year ago

$("#myFunction, #callingFunction").on('change', doSomething)

ami070ipec · Accepted Answer · 2015-03-03 12:02:45Z

0

If you are re-assigning the some behavior after the initial event. I'm not sure if you're looking to chain events, eg

$('ele')
.click(function(){})
.hover(function(){})

It depends on what you're doing, entirely.

answered Mar 3, 2015 at 12:02

ami070ipec

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