How to echo JSON string and replace part of that string at the same time?

Question

I'm decoding a JSON response and outputting it in a simple table. Here is a sample of the code:

<?php

foreach($results['Events'] as $values)

{
        echo '<tr><td>' . $values['Title'] . '</td>';
        echo '<td>' . $values['Details']['Venue'] . '</td>';
        echo '<td>Event date:' . $values['Details']['Date'] . '</td></tr>';
}

?>

Since Date has a timezone added to it, this is what I get:

Event title | Event venue | Event date
Event one | Venue one | 2016-01-01T00:00:00
Event two | Venue two | 2016-01-02T00:00:00
Event three | Venue three | 2016-01-03T00:00:00

Is there a way to remove "T00:00:00" when echoing the results? This is a desired outcome:

Event title | Event venue | Event date
Event one | Venue one | 2016-01-01
Event two | Venue two | 2016-01-02
Event three | Venue three | 2016-01-03

For each date, create a new DateTime object, then format is as you want. — gen_Eric
– gen_Eric, Commented Sep 4, 2015 at 14:08

bspellmeyer · Accepted Answer · 2015-09-04 14:10:20Z

5

Use DateTime:

$date = new \DateTime($values['Details']['Date']);
echo '<td>Event date:' . $date->format('Y-m-d') . '</td></tr>';

answered Sep 4, 2015 at 14:10

bspellmeyer

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Comments

Niranjan N Raju · Accepted Answer · 2015-09-04 14:13:16Z

3

you can also use strtotime()

echo '<td>Event date:' . date("Y-m-d",strtotime($values['Details']['Date'])) . '</td></tr>';

answered Sep 4, 2015 at 14:13

Niranjan N Raju

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2 Comments

take2 Over a year ago

Very nice and elegant solution, thank you. I have accepted bspellmeyer's answer because he was the first one to offer the solution.

Thyagi Over a year ago

nice to have a single line solution

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