use namespace with variable in name

Question

I am working on something, just practicing and I don't have that much experience. I am using namespaces and I have one functions in class namespaced under 'App\Core' which should include another file with different class and namespaced under 'App\Diff' and return that new class. i.e.

namespace App\Core;

class Test {
    public function testFunc($file) {
        require_once "../folder/" . $file . ".php";
        return new $file();
    }
}

now class inside $file

namespace App\Diff;

class Test2 {
}

I tried something like return

new App\Diff . "\{$file()}";

but I got an error "Class App\Code\App\Diff not found ..."

What happen if you put another backslash at the front like new \App\Diff ? — frz3993
– frz3993, Commented Feb 26, 2017 at 17:19
How do you instantiate the Test class and call the testFunc() ? — frz3993
– frz3993, Commented Feb 26, 2017 at 18:14
I call it from another class. use App\Core\Test; and call it from within a function public function function callTest() { $a = $this->b->testFunc('ClassName'); } and b is an instance of Test class — mishke
– mishke, Commented Feb 26, 2017 at 18:21

Community · Accepted Answer · 2017-05-23 11:46:15Z

2

As frz3993 mentions that first you have go in global space than you can access \App\Diff and your class . see the manual
Second problem i don't have correct solution but you can see last answer of csga5000 link & manual

namespace App\Core;

class Test {
    public function testFunc($file) {
        require_once "../folder/" . $file . ".php";
         $f = "\\App\\Diff\\".$file ;
         return new $f;
    }
}

edited May 23, 2017 at 11:46

CommunityBot

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answered Feb 26, 2017 at 18:29

gaurav

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1 Comment

mishke Over a year ago

That actually worked. Thanks, I'll read it and continue with my project.

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