Remove from array if not present in another array

Question

var allowedIds = [1000, 1001, 1002, 1003, 1004];
var idsToCheck = [1000, 1001, 1005, 1006];

I'm looking to find a way to remove 1005 & 1006 from arrayToCheck as those ids are not in the allowedIds array

any help would be appreciated.

thanks!

do a array .filter on idstocheck.. you can filter out the values that is not present in allowedIds by using the .indexOf. — Jalil
– Jalil, Commented May 4, 2017 at 15:33

madox2 · Accepted Answer · 2017-05-04 15:37:54Z

11

You can iterate over idsToCheck using Array.prototype.filter() to filter out all ids which are not in allowedIds. For example:

const checkedIds = idsToCheck.filter(id => allowedIds.includes(id));

Note: using ES6 features: arrow functions and Array.prototype.includes(). To use it in older browsers check for compatibility.

Here is an alternative implementation with better browser compatiblity:

var checkedIds = idsToCheck.filter(function(id) {
  return allowedIds.indexOf(id) > -1;
});

answered May 4, 2017 at 15:27

madox2

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