PHP for loop adding commas

Question

I have this for loop:

for($i=0; $i < $N; $i++)
   $require_1 .= $require[$i] . " ";

I would like it to place a comma on the end of the first word, if there's 2 words in the string. However if there's only 1 word in the string I want it left alone.

I understand I need to use an if statement, based on $i. However I'm not sure how I do this.

What does $require contain? Where are the words?

Felix Kling
– Felix Kling

2011-01-15 22:50:42 +00:00
Commented Jan 15, 2011 at 22:50 — Felix Kling
– Felix Kling, Commented Jan 15, 2011 at 22:50

PeeHaa · Accepted Answer · 2011-01-15 22:46:59Z

5

$require_1 = implode(', ', $require);

Will this do? It places a comma and a space after each item

answered Jan 15, 2011 at 22:46

PeeHaa

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Comments

sissonb · Accepted Answer · 2011-01-15 22:54:22Z

2

This is a trick I use a lot to make strings like that,

$require_1 = "";
for ($i = 0; $i < $N; $i++) {
    if ($require_1 == '' || $require_1 == '&') {
        $require_1 .= $require[$i];
    }
    else {
        $require_1 .= ', '.$require[$i];
    }
}

edit - added another condition for '&' char

edited Jan 15, 2011 at 22:54

answered Jan 15, 2011 at 22:47

sissonb

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Comments

dqhendricks · Accepted Answer · 2011-01-15 22:48:03Z

0

for($i=0; $i < $N; $i++) {
    $require[$i] = explode(' ', $require[$i]);
    $require[$i] = implode(', ', $require[$i]);
    $require_1 .= $require[$i] . " ";
}

this will break up each string, and add commas beteen each word.

answered Jan 15, 2011 at 22:48

dqhendricks

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1 Comment

Dean Over a year ago

Thanks, however it treats '&' as a word. How can I stop it placing a comma after &? EDIT: It also puts a comma after any space. So say I have Test (testing) it equals to Test, (testing).

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