Take multiple urls in python using request.GET

Question

I am trying to take multiple URL's separated by comma and put them in list in python.

I tried:

url = request.GET.get('url').split(',')  #accept url seperated by comma
data= []
data.append(requests.get(url).content)

The above code did not work for obvious reasons. How can I accept multiple url separated by comma using request.GET

url is your list.

willeM_ Van Onsem
– willeM_ Van Onsem

2020-02-26 11:52:11 +00:00
Commented Feb 26, 2020 at 11:52 — willeM_ Van Onsem
– willeM_ Van Onsem, Commented Feb 26, 2020 at 11:52

willeM_ Van Onsem · Accepted Answer · 2020-02-26 11:53:22Z

1

url is a list of URLs. Hence you can perform a mapping. For example with list comprehension:

urls = request.GET.get('url').split(',')
data = [requests.get(url).content for url in urls]

answered Feb 26, 2020 at 11:53

willeM_ Van Onsem

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Comments

General4077 · Accepted Answer · 2021-04-22 20:38:39Z

0

To extend Willem's answer a step further, you can also do the same thing with a dictionary. This is useful if you will want to use the url as a key to retrieve the content later.

urls = request.GET.get('url').split(',')
data = {url: requests.get(url).content for url in urls}

edited Apr 22, 2021 at 20:38

answered Feb 26, 2020 at 12:28

General4077

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