PHP parameters inside url cumulated parameter

Question

lets say I have an url

http://www.somepage.com/clicker.php?id_campaign=8&id_email=9324&url=https://www.google.com/search?q=dog&amp;sxsrf=ALeKk019eteEpAwVf2Fk4qYo7TiwhuMQ_Q:1596666153666&amp;source=lnms&amp;tbm=isch&amp;sa=X&amp;ved=2ahUKEwiqzqf3jIXrAhUisaQKHRayBWAQ_AUoAXoECBkQAw&amp;biw=1920&amp;bih=921#imgrc=M4wsJO0A7OQfTM

and im trying to get out the parameters id_campaign, id_email and url however, using the code:

$url = htmlspecialchars_decode($url);
$parts = parse_url($url);
parse_str($parts['query'], $query);

when printing $parts['query'] it only gives me:

https://www.google.com/search?q=dog

because rest of the url it consider as another parameter...

so how do I get all the url parameter out of $url?

You need really should url_encode google.com/… before putting it in the url. — AbraCadaver
– AbraCadaver, Commented Aug 5, 2020 at 23:05
$url is variable i cant modify in any way for other important reasons, i can only change the way i parse parameters out of $url — Jiri Zaloudek
– Jiri Zaloudek, Commented Aug 5, 2020 at 23:09

Jeto · Accepted Answer · 2020-08-06 00:48:28Z

1

In an ideal scenario, the URLs passed within the query would be URL-encoded, as opposed to HTML-encoded.

What you could do in your case is manually replace all & by something temporary and then replace them all back after parsing the URL. This is not exactly pretty, but works:

$url = str_replace('&amp;', '__TEMP__', $url);

$parts = parse_url($url);
parse_str($parts['query'], $query);

$urlParam = str_replace('__TEMP__', '&', $query['url']);

echo $urlParam;

Demo

answered Aug 6, 2020 at 0:48

Jeto

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