Javascript not working with PHP echo statements

Question

So, I'm using jQuery with PHP, and, I am echoing out a button:

echo '<input type="button" id="button" value="Info" style="float: right;"/>';

Pretty simple, I tried using "\" for the quotations, but, that didn't make any difference (for those who will point it out.

Anyway, the jQuery portion is pretty simple:

        $("#button").click(function() {
        alert("Clicked");
    });

Within the $(document).ready(function(){});

The echo is passed through an ajax call. If that makes any difference, and.

I do not get the alert. So if anyone can pinpoint the solution that would be great.

It doesn't matter who generated the code, but it matters what actually has been generated. Have you seen the final html in your browser? — zerkms
– zerkms, Commented Feb 29, 2012 at 22:34
Does it work if you just make an html file with only those two elements. It's probably something else that's causing the problem. Also what browser did you test wtih? — Cfreak
– Cfreak, Commented Feb 29, 2012 at 22:35
<input type="button" id="button" value="Info" style="float: right; "/> - is what was generated according to firebug. There are multiple buttons mind you. Should it be kept as a class or id? — CCates
– CCates, Commented Feb 29, 2012 at 22:36
If you're loading the html from an ajax, you need to bind the event with live instead of click like @ken has done below in his answer. The element doesn't exist when the event is bound, so it doesn't work. — menacingly
– menacingly, Commented Feb 29, 2012 at 22:39

Ken Wheeler · Accepted Answer · 2012-02-29 22:35:44Z

3

echo '<input type="button" id="button" value="Info" style="float: right;"/>';

$("input#button").live('click',function() {
        alert("Clicked");
});

answered Feb 29, 2012 at 22:35

Ken Wheeler

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1 Comment

CCates Over a year ago

Worked, thanks, now, I just need to figure out parent classes, and, get the parent ID. That is something I can figure out on my own.

Mark Ursino · Accepted Answer · 2012-03-01 18:54:34Z

0

Try using " instead of ' for the quotes on the outside as PHP does not evaluate things inside single quotes.

edited Mar 1, 2012 at 18:54

Mark Ursino

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answered Feb 29, 2012 at 22:35

Daniel

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