echo javascript from php not working?

Question

So, in an html page I'm trying to have a php segment echo some javascript code, as seen here:

<?php
    echo "This was legitimately hit";
    if(!empty($_POST['name']))
    {
        echo '<script type="text/javascript">alert("We got the name");</script>';
    }
    else
    {
        echo '<script type="text/javascript">alert("We DID NOT get the name");</script>';
    }
?>

and from what I've read online, this seems to be a legitimate way of doing things, but the page seems to be reading the first part up until the first closing chevron (seen just below here) as a comment.

<?php
    echo "This was legitimately hit";
    if(!empty($_POST['name']))
    {
        echo '<script type="text/javascript">

Then it reads the else and next echo as plain text, and puts it on the webpage. the next javascript code block then gets read as a regular javascript code block, so the page does a pop-up saying it did not get the name. The closing bracket and closing chevron then just get output as more text.

So in the end the page just ends up having

alert("We got the name")'; } else { echo ''; } ?>

printed on it as plain text, and has a pop-up that says we received no name.

What is going wrong here?

I don't think this is the real code except you are writing the code in an environment where html tags are not allowed - like in Content Management System html editor — codingbiz
– codingbiz, Commented Jun 1, 2012 at 19:23

Dan · Accepted Answer · 2012-06-01 19:40:03Z

4

Sounds like the file isn't being processed as PHP. Does the file name end in .php? Are you sure PHP is installed and hooked up correctly to the web server?

edit: To handle the Facebook requests in the same page:

<?php

if (isset($_POST['facebook_request_field'])) {
  // handle the Facebook request, output any necessary response
  // then exit
  exit;
}

?>
<!-- display the web page normally here -->

So for your test page:

<?php

if (isset($_POST['name'])) {
  echo '<script type="text/javascript">alert("got a name!");</script>';
  exit;
}

?>
<script type="text/javascript">alert("No name.");</script>

(That's actually identical in function to what you already have, so maybe I'm misunderstanding the purpose.)

edited Jun 1, 2012 at 19:40

answered Jun 1, 2012 at 19:08

Dan

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15 Comments

ZachLHelms Over a year ago

Well this is all in an html page.

CM Kanode Over a year ago

php will not execute in an html page. It needs to "be" a php page (file extension of php, not html) for the php code to be processed.

Scott Saunders Over a year ago

Servers can be set up to process .html pages as php. @Zahel: see if any php at all runs correctly before troubleshooting the javascript.

ZachLHelms Over a year ago

@ScottSaunders, it runs a regular php just fine.

Dan Over a year ago

By "regular php," do you mean a file ending in .php?

|

Scott Saunders · Accepted Answer · 2012-06-01 19:09:29Z

1

Between We got the signed request and We got the name, I think you haven't given us the actual code that's causing the error. Double check that, and make sure you don't have any stray single quotes before your alert call.

answered Jun 1, 2012 at 19:09

Scott Saunders

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2 Comments

Scott Saunders Over a year ago

How do you explain the different strings?

ZachLHelms Over a year ago

Ah, I see what you mean, the "signed request" was bit was not supposed to be there, it was supposed to be "the name". All the code here is referring to the same code, I just overwrote something by accident.

Gerard Yin · Accepted Answer · 2012-06-01 19:09:22Z

0

There are missing ; after the alert. Have you tried correcting this first?

answered Jun 1, 2012 at 19:09

Gerard Yin

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3 Comments

ZachLHelms Over a year ago

just tried this, changed nothing. Will change the initial post to reflect this.

codingbiz Over a year ago

that should not stop php from printing the string

Scott Saunders Over a year ago

it also wouldn't stop the javascript from running

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