PHP passing variable in an array

Question

I have a function like this

function login_redirect($redirect, $vars = array())
{
    return $redirect;
}

I would like to pass this variable in that array

$user = null

I tried like this

function login_redirect($redirect, $vars = array($user => null))
{
    return $redirect;
}

But I'm getting error. Can anyone correct me?

Thanks

ThiefMaster · Accepted Answer · 2012-03-27 15:07:14Z

3

You defined the array key incorrectly. The following works:

function login_redirect($redirect, $vars = array('user' => null))
{
    return $redirect;
}

answered Mar 27, 2012 at 15:07

ThiefMaster

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Comments

Hubro · Accepted Answer · 2012-03-27 15:08:30Z

1

I'm assuming this is what you're trying to do:

function login_redirect($redirect, $vars = array())
{
    return $redirect;
}

// Redirect:
login_redirect("somepath", array("user" => $user));

Now the array you pass to login_redirect will contain the value of $user

answered Mar 27, 2012 at 15:08

Hubro

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Now I'm guessing this isn't what you're trying to do at all. I'll just stay here in the corner and try not to attract attention

Thanks for your answer. ThiefMaster's code working correctly.